- Measured at 45 mi/h. The peak-hour directional traffic flow is 1300 vehicles with 6% large trucks and buses and 2% recreational vehicles (If the peak-hour factor is 0.85, determine the highway's level of service. 5.(17) A new four-lane divided multilane highway (two lanes in each direction) is being planned with 12-ft lanes, 6-ft shoulders on both sides, and a 50-mi/h speed limit.
- Where the peak-hour factor is known, it may be used to convert a peak-hour volume to a peak rate of flow, as follows: v = V/PHF (2-3) Where v = rate of flow for a peak 15-min period (vph), V = peak-hour volume (vph), and PHF = peak-hour factor. Equation 2-3 need not be used to estimate peak flow rates where traffic counts are available.
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Peak Hour Volume, Design Flow Rate, PHF
It is commonly known in your area that the heaviest traffic flow rates occur between 4:00 PM and 6:30 PM. Your assignment for the day is to find the peak hour volume, peak hour factor (PHF), and the actual or design flow rate for an existing one-lane approach. To do this, you obtain a click-counter and position yourself at the intersection. For each fifteen-minute interval, you record the numbers of right-turns, left-turns, straight-through trucks, and straight-through passenger cars. Your tabulated values are as shown below.
| Time Interval | Left Turns | Right Turns | ST Trucks | ST Cars |
| 4:00-4:15 | 5 | 10 | 6 | 30 |
| 4:15-4:30 | 6 | 15 | 8 | 26 |
| 4:30-4:45 | 4 | 7 | 10 | 35 |
| 4:45-5:00 | 7 | 16 | 8 | 40 |
| 5:00-5:15 | 10 | 13 | 6 | 49 |
| 5:15-5:30 | 9 | 12 | 12 | 55 |
| 5:30-5:45 | 14 | 15 | 8 | 65 |
| 5:45-6:00 | 12 | 12 | 10 | 50 |
| 6:00-6:15 | 10 | 9 | 8 | 39 |
| 6:15-6:30 | 9 | 12 | 4 | 30 |
If a truck is equal to 1.5 passenger cars and a right-turn is as well, and if a left-turn is equal to 2.5 passenger cars, then calculate the peak hour volume, peak hour factor (PHF), and the actual (design) flow rate for this approach.
[Solution Shown Below]
Solution
The first step in this solution is to find the total traffic volume for each 15 minute period in terms of passenger car units. This is done by multiplying the number of trucks by 1.5, the number of right turns by 1.5, and the number of left turns by 2.5. We then add these three numbers and the volume of straight-through cars together to get the total volume of traffic serviced in each interval. Once we have this, we can locate the hour with the highest volume and the 15 minute interval with the highest volume. The peak hour is shown in blue below with the peak 15 minute period shown in a darker shade of blue.
| Time Interval | Interval Volume (pcu) |
| 4:00-4:15 | 67 |
| 4:15-4:30 | 76 |
| 4:30-4:45 | 71 |
| 4:45-5:00 | 94 |
| 5:00-5:15 | 103 |
| 5:15-5:30 | 114 |
| 5:30-5:45 | 135 |
| 5:45-6:00 | 113 |
| 6:00-6:15 | 90 |
| 6:15-6:30 | 77 |
The peak hour volume is just the sum of the volumes of the four 15 minute intervals within the peak hour (464 pcu). The peak 15 minute volume is 135 pcu in this case. The peak hour factor (PHF) is found by dividing the peak hour volume by four times the peak 15 minute volume.
PHF = 464 /(4 * 135) = 0.86
The actual (design) flow rate can be calculated by dividing the peak hour volume by the PHF, 464/0.86 = 540 pcu/hr, or by multiplying the peak 15 minute volume by four, 4 * 135 = 540 pcu/hr.
